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(D) According to Boyle's Law at constant temperature,$P \propto \frac{1}{V}$,which implies $P_1 V_1 = P_2 V_2$.Let the initial pressure be $P_1 = P$.T

Vedclass · Accepted Answer

$4.76$

Vedclass · Answer

(D) According to Boyle's Law at constant temperature,$P \propto \frac{1}{V}$,which implies $P_1 V_1 = P_2 V_2$.Let the initial pressure be $P_1 = P$.The new pressure is $P_2 = P + 0.05P = 1.05P$.Substituting these into the equation: $P V_1 = 1.05P V_2$.Solving for the new volume: $V_2 = \frac{V_1}{1.05} \approx 0.9524 V_1$.The change in volume is $\Delta V = V_2 - V_1 = 0.9524 V_1 - V_1 = -0.0476 V_1$.The percentage decrease in volume is $\frac{|\Delta V|}{V_1} 	imes 100 = 0.0476 	imes 100 = 4.76 \%$.

At constant temperature,increasing the pressure of a gas by $5 \%$ its volume will decrease by (in $\%$)

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