Bansal,Gupta,and Singhal together can complet | vedclass

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(B) Let the work done by Bansal,Gupta,and Singhal in one day be $B, G,$ and $S$ respectively.Given: $B + G + S = \frac{1}{4}$ (Equation $1$)$B + G = \

Vedclass · Accepted Answer

$12$

Vedclass · Answer

(B) Let the work done by Bansal,Gupta,and Singhal in one day be $B, G,$ and $S$ respectively.Given: $B + G + S = \frac{1}{4}$ (Equation $1$)$B + G = \frac{1}{4.8} = \frac{1}{24/5} = \frac{5}{24}$ (Equation $2$)$G + S = \frac{1}{8}$ (Equation $3$)From Equation $1$ and Equation $2$,we get $S = \frac{1}{4} - \frac{5}{24} = \frac{6-5}{24} = \frac{1}{24}$. So,Singhal takes $24 \, 	ext{days}$.From Equation $1$ and Equation $3$,we get $B = \frac{1}{4} - \frac{1}{8} = \frac{2-1}{8} = \frac{1}{8}$. So,Bansal takes $8 \, 	ext{days}$.Now,substitute $B$ in Equation $2$: $\frac{1}{8} + G = \frac{5}{24} \implies G = \frac{5}{24} - \frac{1}{8} = \frac{5-3}{24} = \frac{2}{24} = \frac{1}{12}$.Therefore,Gupta alone can complete the work in $12 \, 	ext{days}$.

Bansal,Gupta,and Singhal together can complete a work in $4 \, \text{days}$. If Bansal and Gupta together can complete the work in $4 \frac{4}{5} \, \text{days}$,and Gupta and Singhal together can do it in $8 \, \text{days}$,then Gupta alone can complete the work in (in $\text{days}$):

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