Calculate the concentration of H_3O^{+} ion i | vedclass

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Question

(A) The relationship between $pH$ and the concentration of hydronium ions is given by the formula: $pH = -\log[H_3O^{+}]$.Given $pH = 2.8$,we have $2.

Vedclass · Accepted Answer

$1.585 	imes 10^{-3} \ mol \ dm^{-3}$

Vedclass · Answer

(A) The relationship between $pH$ and the concentration of hydronium ions is given by the formula: $pH = -\log[H_3O^{+}]$.Given $pH = 2.8$,we have $2.8 = -\log[H_3O^{+}]$,which implies $\log[H_3O^{+}] = -2.8$.To find $[H_3O^{+}]$,we take the antilog of $-2.8$: $[H_3O^{+}] = 10^{-2.8}$.$[H_3O^{+}] = 10^{0.2} 	imes 10^{-3}$.Since $10^{0.2} \approx 1.585$,the concentration is $[H_3O^{+}] = 1.585 	imes 10^{-3} \ mol \ dm^{-3}$.

Calculate the concentration of $H_3O^{+}$ ion if the $pH$ of the solution is $2.8$.

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