Calculate the degree of dissociation of $0.01 \ M$ acetic acid at $25^{\circ} C$ given that the molar conductivity at concentration $c$ is $\Lambda_{c} = 15.0 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ and the limiting molar conductivity is $\Lambda_0 = 300 \ \Omega^{-1} \ cm^2 \ mol^{-1}$.
- A$0.042$
- B$0.035$
- C$0.025$
- D$0.05$
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View SolutionWhat must be the molarity of $BaCl_2$ solution to have molar conductivity $240 \text{ } \Omega^{-1} \text{cm}^2 \text{mol}^{-1}$ and conductivity $0.012 \text{ } \Omega^{-1} \text{cm}^{-1}$ at $25^{\circ} \text{C}$ (in $\text{ M}$)?
DifficultMHT CET 2026
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