Calculate the mean of the following frequency | vedclass

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(A) To calculate the mean,we first find the class mark $(x_i)$ for each class interval using the formula: $x_i = \frac{	ext{Lower limit} + 	ext{Uppe

Vedclass · Accepted Answer

$31.4$

Vedclass · Answer

(A) To calculate the mean,we first find the class mark $(x_i)$ for each class interval using the formula: $x_i = \frac{	ext{Lower limit} + 	ext{Upper limit}}{2}$.$1$. For $10-20$: $x_1 = \frac{10+20}{2} = 15$$2$. For $20-30$: $x_2 = \frac{20+30}{2} = 25$$3$. For $30-40$: $x_3 = \frac{30+40}{2} = 35$$4$. For $40-50$: $x_4 = \frac{40+50}{2} = 45$$5$. For $50-60$: $x_5 = \frac{50+60}{2} = 55$Now,calculate $f_i x_i$ for each class:- $12 	imes 15 = 180$- $16 	imes 25 = 400$- $8 	imes 35 = 280$- $6 	imes 45 = 270$- $8 	imes 55 = 440$Sum of frequencies $(\sum f_i)$: $12 + 16 + 8 + 6 + 8 = 50$.Sum of products $(\sum f_i x_i)$: $180 + 400 + 280 + 270 + 440 = 1570$.Mean $(\bar{x})$ = $\frac{\sum f_i x_i}{\sum f_i} = \frac{1570}{50} = 31.4$.

Class	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$12$	$16$	$8$	$6$	$8$

Calculate the mean of the following frequency distribution:

Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$

Frequency $12$ $16$ $8$ $6$ $8$

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Calculate the mean of the following frequency distribution: Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ Frequency $12$ $16$ $8$ $6$ $8$