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Question

(B) The reaction starts with cyclohexylideneacetic acid reacting with excess $CH_3Li$. $CH_3Li$ acts as a nucleophile and attacks the carbonyl carbon

Vedclass · Accepted Answer

Sodium cyclohexylidene acetate

Vedclass · Answer

(B) The reaction starts with cyclohexylideneacetic acid reacting with excess $CH_3Li$. $CH_3Li$ acts as a nucleophile and attacks the carbonyl carbon of the carboxylic acid group. After protonation,this forms a ketone,specifically cyclohexylideneacetone (compound $A$). Compound $A$ contains a methyl ketone group $(CH_3-C=O)$,which undergoes the haloform reaction with $I_2$ and $NaOH$. The haloform reaction converts the methyl ketone into a carboxylate salt and produces iodoform $(CHI_3)$. Therefore,the final product $(B)$ is the sodium salt of the corresponding acid,which is sodium cyclohexylideneacetate.

Compound $(B)$ is

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