Consider a class of 5 girls and 7 boys. The n | vedclass

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(C) Total number of ways to select $2$ girls from $5$ and $3$ boys from $7$ without any restriction is given by $^5C_2 	imes ^7C_3 = 10 	imes 35 = 3

Vedclass · Accepted Answer

$300$

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(C) Total number of ways to select $2$ girls from $5$ and $3$ boys from $7$ without any restriction is given by $^5C_2 	imes ^7C_3 = 10 	imes 35 = 350$.Now,we calculate the number of teams where both specific boys $A$ and $B$ are present together.If $A$ and $B$ are both in the team,we need to select $1$ more boy from the remaining $5$ boys $(7 - 2 = 5)$ and $2$ girls from $5$.Number of such teams $= ^5C_1 	imes ^5C_2 = 5 	imes 10 = 50$.The number of teams where $A$ and $B$ are not together is the total number of teams minus the number of teams where they are together.Required number of ways $= 350 - 50 = 300$.

Consider a class of $5$ girls and $7$ boys. The number of different teams consisting of $2$ girls and $3$ boys that can be formed from this class,if there are two specific boys $A$ and $B$ who refuse to be members of the same team,is

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