Consider diffraction of light through a recta | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The angular width of the central diffraction maximum for a slit of width $a$ is given by $	heta = \frac{2\lambda}{a}$.Given that the slit is rect

Vedclass · Accepted Answer

The central diffraction peak is wider in the vertical direction than the horizontal direction.

Vedclass · Answer

(A) The angular width of the central diffraction maximum for a slit of width $a$ is given by $	heta = \frac{2\lambda}{a}$.Given that the slit is rectangular with width $w$ and height $h$,where $w = 2h$.The diffraction pattern is formed by the superposition of diffraction effects in the horizontal and vertical directions.The angular width in the horizontal direction is $	heta_w = \frac{2\lambda}{w}$ and in the vertical direction is $	heta_h = \frac{2\lambda}{h}$.Since $w = 2h$,we have $	heta_w = \frac{2\lambda}{2h} = \frac{\lambda}{h}$.Comparing the two,$	heta_h = \frac{2\lambda}{h}$ and $	heta_w = \frac{\lambda}{h}$,it is clear that $	heta_h > 	heta_w$.Therefore,the central diffraction peak is wider in the vertical direction than in the horizontal direction.

Consider diffraction of light through a rectangular slit which is twice as wide as it is high. Which of the following statements is true?

Similar Questions

$A$ diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light,then:

Monochromatic light of wavelength $580 \,nm$ is incident on a slit of width $0.30 \,mm$. The screen is $2 \,m$ from the slit. The width of the central maximum is ........... $\times 10^{-3} \,m$.

$A$ slit of width $a$ is illuminated by monochromatic light of wavelength $650 \ nm$. The value of the slit width $a$ when the first minimum is formed at a diffraction angle of $30^\circ$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module