Consider the nuclear reaction $X^{200} \rightarrow A^{110} + B^{90}$. If the binding energy per nucleon for $X, A,$ and $B$ is $7.4 \, MeV, 8.2 \, MeV,$ and $8.2 \, MeV$ respectively, what is the energy released in $MeV$?

If an electron and a positron annihilate,the energy released is ........

The binding energy per nucleon for $_8O^{16}$ and $_8O^{17}$ are $7.97 \, MeV$ and $7.75 \, MeV$ respectively. The energy required to remove a neutron from $_8O^{17}$ is (in $MeV$):

The radionuclide $^{11}_{6}C$ decays by $\beta^+$ emission. Given that $m(^{11}_{6}C) = 11.011434 \ u$,$m(^{11}_{5}B) = 11.009305 \ u$,$m_e = 0.000548 \ u$,and $1 \ u = 931.5 \ MeV/c^2$. The $Q$-value of this decay process is:

$A$ given coin has a mass of $3.0\; g$. Calculate the nuclear energy that would be required to separate all the neutrons and protons from each other. For simplicity, assume that the coin is entirely made of $_{29}^{63} Cu$ atoms (of mass $62.92960\; u$).

The value of $1 \, \text{a.m.u.}$ is equivalent to how many $MeV/c^2$?