The domain of the function f(x) = frac{sqrt{1 | vedclass

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(D) For the function $f(x) = \frac{\sqrt{1 + x} - \sqrt{1 - x}}{x}$ to be defined:$1$. The expression under the square root must be non-negative:$1 +

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$[-1, 1] \setminus \{0\}$

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(D) For the function $f(x) = \frac{\sqrt{1 + x} - \sqrt{1 - x}}{x}$ to be defined:$1$. The expression under the square root must be non-negative:$1 + x \ge 0 \implies x \ge -1$$1 - x \ge 0 \implies x \le 1$Combining these,we get $x \in [-1, 1]$.$2$. The denominator cannot be zero:$x 
eq 0$Combining both conditions,the domain is $[-1, 1] \setminus \{0\}$.

The domain of the function $f(x) = \frac{\sqrt{1 + x} - \sqrt{1 - x}}{x}$ is

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