Domain of the real valued function f(x) = fra | vedclass

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(B) The function $f(x) = \frac{x+2}{9-x^{2}}$ is defined for all real values of $x$ except where the denominator is zero. Setting the denominator to z

Vedclass · Accepted Answer

$R - \{-3, 3\}$

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(B) The function $f(x) = \frac{x+2}{9-x^{2}}$ is defined for all real values of $x$ except where the denominator is zero. Setting the denominator to zero: $9 - x^{2} = 0$. This implies $x^{2} = 9$,so $x = \pm 3$. Thus,the function is undefined at $x = 3$ and $x = -3$. Therefore,the domain of the function is the set of all real numbers except $\{-3, 3\}$,which is written as $R - \{-3, 3\}$.

Domain of the real valued function $f(x) = \frac{x+2}{9-x^{2}}$ is

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