The nuclear reaction _{17}Cl^{37} + _1H^2 to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The given reaction is $_{17}Cl^{37} + _1H^2 	o _{18}Ar^{38} + _0n^1$. In this process,a stable nucleus of chlorine is bombarded with a projectile

Vedclass · Accepted Answer

Artificial transmutation of chlorine

Vedclass · Answer

(C) The given reaction is $_{17}Cl^{37} + _1H^2 	o _{18}Ar^{38} + _0n^1$. In this process,a stable nucleus of chlorine is bombarded with a projectile (deuteron,$_1H^2$) to form a new element,argon,and a neutron. This is a classic example of artificial transmutation,where one element is converted into another by nuclear bombardment.

The nuclear reaction $_{17}Cl^{37} + _1H^2 \to _{18}Ar^{38} + _0n^1$ represents:

Similar Questions

$_6C^{12}$ and $_1T^3$ are formed in nature due to the nuclear reaction of a neutron with:

In the nuclear equation $_{11}Na^{23} + _{1}H^{1} \to _{12}Mg^{23} + x$,what does $x$ represent?

$A$ photon of hard gamma radiation knocks a proton out of a $_{12}^{24}Mg$ nucleus to form:

Which of the following can be used to convert $_7^{14}N$ into $_8^{17}O$?

Identify $X$ in $_{16}S^{32} + X \to _{15}P^{30} + _{2}He^{4}$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module