The equation of the line passing through $(1, 2)$ and perpendicular to $3x + 4y + 5 = 0$ is

The equation of the line passing through the point $(-1, 3)$ in symmetrical form,when the angle made by the line with the positive direction of the $X$-axis is $120^{\circ}$,is given by:

The line passing through $\left(-1, \frac{\pi}{2}\right)$ and perpendicular to $\sqrt{3} \sin \theta + 2 \cos \theta = \frac{4}{r}$ is:

One diagonal of a square is along the line $8x - 15y = 0$ and one of its vertices is $(1, 2)$. Then the equations of the sides of the square passing through this vertex are:

The equation of the straight line which is perpendicular to $y = x$ and passes through $(3, 2)$ is

If two vertical poles of heights $20\,m$ and $80\,m$ stand apart on a horizontal plane,then the height (in $m$) of the point of intersection of the lines joining the top of each pole to the foot of the other is: