The equation of the line passing through the point $(-1, 3)$ in symmetrical form,when the angle made by the line with the positive direction of the $X$-axis is $120^{\circ}$,is given by:
- A$\frac{x+1}{-1/2} = \frac{y-3}{\sqrt{3}/2} = r$
- B$\frac{x+1}{1/2} = \frac{y+3}{\sqrt{3}/2} = r$
- C$\frac{x+1}{-1/2} = \frac{y+3}{\sqrt{3}/2} = r$
- D$\frac{x+1}{1/2} = \frac{y-3}{\sqrt{3}/2} = r$
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