Error in the measurement of radius of the sphere is $2 \%$. The error in the calculated value of its volume is (in $\%$)

  • A
    $3$
  • B
    $2$
  • C
    $6$
  • D
    $9$

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$A$ physical quantity $P$ is given by $P = \frac{A^3 B^{1/2}}{C^{-4} D^{3/2}}$. The quantity which brings in the maximum percentage error in $P$ is

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