Ethanoic acid $+$ $3$-methylbutan-$1$-ol $\underset{\text{traces } H_2SO_4}{\longleftrightarrow} (A)$; Compound $(A)$ is

  • A
    Option A
  • B
    Option B
  • C
    Option C
  • D
    Option D

Explore More

Similar Questions

When compound $X$ is oxidised by acidified potassium dichromate,compound $Y$ is formed. Compound $Y$ on reduction with $LiAlH_4$ gives $X$. $X$ and $Y$ respectively are:

An ester $(A)$ with molecular formula $C_9H_{10}O_2$ is reacted with an excess of $CH_3MgBr$. The resulting product is treated with concentrated $H_2SO_4$ to form an olefin $(B)$. Ozonolysis of $(B)$ yields a ketone with the formula $C_8H_8O$. What is the structure of $(A)$?

In the given reaction: $NH_2-CH_2-CH_2-NH_2 + C_2H_5OOC-COOC_2H_5 \xrightarrow{\text{Pyridine}} [X]$,$[X]$ will be:

Match List-$I$ with List-$II$.
List-$I$:
$(a)$ $\text{Benzene} \xrightarrow[\text{CuCl}]{\text{CO, HCl, Anhyd. AlCl}_3} \text{Benzaldehyde}$
$(b)$ $R-CO-CH_3 + NaOX \rightarrow$
$(c)$ $R-CH_2-OH + R'COOH \xrightarrow{\text{Conc. H}_2\text{SO}_4}$
$(d)$ $R-CH_2COOH \xrightarrow[(ii) H_2O]{(i) X_2/\text{Red P}} R-CH(X)COOH$
List-$II$:
$(i)$ $\text{Hell-Volhard-Zelinsky reaction}$
(ii) $\text{Gattermann-Koch reaction}$
(iii) $\text{Haloform reaction}$
(iv) $\text{Esterification}$
Choose the correct answer from the options given below.

Match the following chemical reactions:
$a$. $\text{Toluene} \xrightarrow[(ii) H^+/H_2O]{(i) CrO_2Cl_2/CS_2}$$p$. $\text{Kolbe's electrolysis}$
$b$. $CH_3COOK \xrightarrow{\text{electrolysis}}$$q$. $\text{Etard reaction}$
$c$. $CH_3Br \xrightarrow{Na, \text{dry ether}}$$r$. $\text{Wurtz reaction}$
$d$. $\text{Benzene} \xrightarrow{CH_3Cl, AlCl_3}$$s$. $\text{Friedel-Crafts alkylation}$

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo