Ethylene reacts with Br_2 to give 1,2text{-di | vedclass

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(B) The reaction of ethylene $(CH_2=CH_2)$ with $Br_2$ follows an electrophilic addition mechanism.The $\pi$ electrons of the double bond attack the b

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(B) The reaction of ethylene $(CH_2=CH_2)$ with $Br_2$ follows an electrophilic addition mechanism.The $\pi$ electrons of the double bond attack the bromine molecule,leading to the formation of a cyclic bromonium ion as a stable intermediate.This is followed by the nucleophilic attack of the bromide ion $(Br^{-})$ from the opposite side to yield $1,2	ext{-dibromoethane}$.The structure of the cyclic bromonium ion is a three-membered ring containing two carbon atoms and one bromine atom with a positive charge.

Ethylene reacts with $Br_2$ to give $1,2\text{-dibromoethane}$. The intermediate of the reaction is:

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