(B) We can express the product as: $103 \times 107 = (100 + 3)(100 + 7)$Using the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$,where $x =

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(B) We can express the product as: $103 \times 107 = (100 + 3)(100 + 7)$Using the algebraic identity $(x + a)(x + b) = x^2 + (a + b)x + ab$,where $x = 100$,$a = 3$,and $b = 7$:$103 \times 107 = (100)^2 + (3 + 7) \times 100 + (3 \times 7)$$= 10000 + (10 \times 100) + 21$$= 10000 + 1000 + 21$$= 11021$