Factorise: x^{3}+x^{2}-4x-4 | vedclass

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(B) Let $f(x) = x^{3} + x^{2} - 4x - 4$.We can factorise by grouping terms:$f(x) = (x^{3} + x^{2}) - (4x + 4)$Factor out the common terms from each gr

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$(x-2)(x+1)(x+2)$

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(B) Let $f(x) = x^{3} + x^{2} - 4x - 4$.We can factorise by grouping terms:$f(x) = (x^{3} + x^{2}) - (4x + 4)$Factor out the common terms from each group:$f(x) = x^{2}(x + 1) - 4(x + 1)$Now,take $(x + 1)$ as a common factor:$f(x) = (x + 1)(x^{2} - 4)$Using the algebraic identity $a^{2} - b^{2} = (a - b)(a + b)$,we can factor $x^{2} - 4$ as $(x - 2)(x + 2)$:$f(x) = (x + 1)(x - 2)(x + 2)$Thus,the factors are $(x - 2)(x + 1)(x + 2)$.

Factorise: $x^{3}+x^{2}-4x-4$

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