Factorise the following expression: 27 x^{3}- | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The given expression is $27 x^{3}-8 y^{3}-54 x^{2} y+36 x y^{2}$.This can be rewritten as $(3x)^3 - (2y)^3 - 3(3x)^2(2y) + 3(3x)(2y)^2$.Recall the

Vedclass · Accepted Answer

$(3x - 2y)^3$

Vedclass · Answer

(A) The given expression is $27 x^{3}-8 y^{3}-54 x^{2} y+36 x y^{2}$.This can be rewritten as $(3x)^3 - (2y)^3 - 3(3x)^2(2y) + 3(3x)(2y)^2$.Recall the algebraic identity: $(a - b)^3 = a^3 - b^3 - 3a^2b + 3ab^2$.Here,$a = 3x$ and $b = 2y$.Substituting these values into the identity,we get $(3x - 2y)^3$.Thus,the factorised form is $(3x - 2y)(3x - 2y)(3x - 2y)$.

Factorise the following expression: $27 x^{3}-8 y^{3}-54 x^{2} y+36 x y^{2}$

Similar Questions

Factorise $169 x^{2}-625$.

Determine the degree of the following polynomial:
$-10$

Expand the following:
$\left(4-\frac{1}{3 x}\right)^{3}$

Find $p(1)$,$p(2)$,and $p(4)$ for the polynomial $p(x) = x^3 + 9x^2 + 23x + 15$.

Classify the following as a constant,linear,quadratic,or cubic polynomial:
$3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module