Factorise the expression: frac{4x^2}{9} - fra | vedclass

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Question

(A) The given expression is $\frac{4x^2}{9} - \frac{1}{25}$.This can be written in the form of $a^2 - b^2$,where $a^2 = \frac{4x^2}{9}$ and $b^2 = \fr

Vedclass · Accepted Answer

$\left(\frac{2}{3}x + \frac{1}{5}\right)\left(\frac{2}{3}x - \frac{1}{5}\right)$

Vedclass · Answer

(A) The given expression is $\frac{4x^2}{9} - \frac{1}{25}$.This can be written in the form of $a^2 - b^2$,where $a^2 = \frac{4x^2}{9}$ and $b^2 = \frac{1}{25}$.Taking the square root,we get $a = \frac{2x}{3}$ and $b = \frac{1}{5}$.Using the algebraic identity $a^2 - b^2 = (a + b)(a - b)$,we substitute the values of $a$ and $b$.Therefore,$\frac{4x^2}{9} - \frac{1}{25} = \left(\frac{2x}{3} + \frac{1}{5}\right)\left(\frac{2x}{3} - \frac{1}{5}\right)$.

Factorise the expression: $\frac{4x^2}{9} - \frac{1}{25}$

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