Find all pairs of consecutive odd positive in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Let $x$ be the smaller of the two consecutive odd positive integers. Then,the other integer is $x+2$.Since both integers are smaller than $10$,we

Vedclass · Accepted Answer

$(5, 7), (7, 9)$

Vedclass · Answer

(A) Let $x$ be the smaller of the two consecutive odd positive integers. Then,the other integer is $x+2$.Since both integers are smaller than $10$,we have:$x+2 $\Rightarrow x Also,the sum of the two integers is more than $11$:$x + (x+2) > 11$$\Rightarrow 2x + 2 > 11$$\Rightarrow 2x > 9$$\Rightarrow x > 4.5$ ... $(ii)$From $(i)$ and $(ii)$,we have $4.5 Since $x$ must be an odd positive integer,the possible values for $x$ are $5$ and $7$.If $x = 5$,the pair is $(5, 7)$.If $x = 7$,the pair is $(7, 9)$.Thus,the required pairs are $(5, 7)$ and $(7, 9)$.

Find all pairs of consecutive odd positive integers,both of which are smaller than $10$,such that their sum is more than $11$.

Similar Questions

Find the solution set of the inequality: $4x + 3 \geq 2x + 17$ and $3x - 5 < -2$.

The feasible region represented by the inequations $2x + 3y \leq 18$,$x + y \geq 10$,$x \geq 0$,$y \geq 0$ is

Find all pairs of consecutive odd positive integers,both of which are smaller than $18$,such that their sum is more than $20$.

Find the set of all values of $x$ satisfying $\frac{x^4 - 4x^3 + 3x^2}{(x^2 - 4)(x^2 - 7x + 10)} \ge 0$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module