Find all the angles of an equilateral triangl | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In an equilateral triangle,all three sides are equal,i.e.,$AB = BC = AC$.
Since the angles opposite to equal sides of a triangle are equal,we hav

Vedclass · Accepted Answer

$60^{\circ},60^{\circ},60^{\circ}$

Vedclass · Answer

(A) In an equilateral triangle,all three sides are equal,i.e.,$AB = BC = AC$.
Since the angles opposite to equal sides of a triangle are equal,we have $\angle A = \angle B = \angle C$.
Let each angle be $x$.
By the angle sum property of a triangle,the sum of all interior angles is $180^{\circ}$.
Therefore,$\angle A + \angle B + \angle C = 180^{\circ}$.
$x + x + x = 180^{\circ}$.
$3x = 180^{\circ}$.
$x = \frac{180^{\circ}}{3} = 60^{\circ}$.
Thus,all the angles of an equilateral triangle are $60^{\circ}, 60^{\circ}, 60^{\circ}$.

Find all the angles of an equilateral triangle.

Similar Questions

In $\Delta ABC$,$AB = AC$ and $AD$ is an altitude to the base $BC$. Prove that $D$ is the midpoint of $BC$.

Prove that in a triangle,other than an equilateral triangle,the angle opposite to the longest side is greater than $\frac{2}{3}$ of a right angle.

In a triangle $ABC$,$D$ is the mid-point of side $AC$ such that $BD = \frac{1}{2} AC$. Show that $\angle ABC$ is a right angle.

In $\Delta PQR$,$\angle Q = \angle R$ and $PQ = 6.5 \, cm$,then find $PR$. (in $, cm$)

It is given that $\triangle ABC \cong \triangle FDE$. If $AB = 5 \, cm$,$\angle B = 40^{\circ}$,and $\angle A = 80^{\circ}$,then which of the following is true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module