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(C) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2)$ and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y

Vedclass · Accepted Answer

$25$

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(C) The area of a triangle with vertices $(x_1, y_1), (x_2, y_2)$ and $(x_3, y_3)$ is given by the formula:Area $= \frac{1}{2} |x_1(y_2 - y_3) + x_2(y_3 - y_1) + x_3(y_1 - y_2)|$Given vertices are $A(3, 2), B(11, 8)$ and $C(8, 12)$.Here,$x_1 = 3, y_1 = 2, x_2 = 11, y_2 = 8, x_3 = 8, y_3 = 12$.Substituting these values into the formula:Area $= \frac{1}{2} |3(8 - 12) + 11(12 - 2) + 8(2 - 8)|$Area $= \frac{1}{2} |3(-4) + 11(10) + 8(-6)|$Area $= \frac{1}{2} |-12 + 110 - 48|$Area $= \frac{1}{2} |50|$Area $= 25$ square units.

Find the area of a triangle having the vertices $A(3, 2), B(11, 8)$ and $C(8, 12)$.

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