Find the centre and radius of the circle x^{2 | vedclass

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(B) The given equation of the circle is $x^{2}+y^{2}-4x-8y-45=0$. Rearranging the terms,we have $(x^{2}-4x) + (y^{2}-8y) = 45$. Completing the square

Vedclass · Accepted Answer

Centre: $(2, 4)$,Radius: $\sqrt{65}$

Vedclass · Answer

(B) The given equation of the circle is $x^{2}+y^{2}-4x-8y-45=0$. Rearranging the terms,we have $(x^{2}-4x) + (y^{2}-8y) = 45$. Completing the square for $x$ and $y$: $(x^{2}-4x+4) + (y^{2}-8y+16) = 45 + 4 + 16$. This simplifies to $(x-2)^{2} + (y-4)^{2} = 65$. Comparing this with the standard form $(x-h)^{2} + (y-k)^{2} = r^{2}$,we get the centre $(h, k) = (2, 4)$ and the radius $r = \sqrt{65}$.

Find the centre and radius of the circle $x^{2}+y^{2}-4x-8y-45=0$.

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