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(B) Given equation is $3x^{2} + 5\sqrt{5}x - 10 = 0$.To factorise,we split the middle term such that the product is $3 	imes (-10) = -30$ and the sum

Vedclass · Accepted Answer

$-2\sqrt{5}, \frac{\sqrt{5}}{3}$

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(B) Given equation is $3x^{2} + 5\sqrt{5}x - 10 = 0$.To factorise,we split the middle term such that the product is $3 	imes (-10) = -30$ and the sum is $5\sqrt{5}$.The factors are $6\sqrt{5}$ and $-\sqrt{5}$,since $(6\sqrt{5}) 	imes (-\sqrt{5}) = -6 	imes 5 = -30$ and $6\sqrt{5} - \sqrt{5} = 5\sqrt{5}$.$3x^{2} + 6\sqrt{5}x - \sqrt{5}x - 10 = 0$$3x(x + 2\sqrt{5}) - \sqrt{5}(x + 2\sqrt{5}) = 0$$(x + 2\sqrt{5})(3x - \sqrt{5}) = 0$Setting each factor to zero:$x + 2\sqrt{5} = 0 \Rightarrow x = -2\sqrt{5}$$3x - \sqrt{5} = 0 \Rightarrow x = \frac{\sqrt{5}}{3}$Thus,the roots are $-2\sqrt{5}$ and $\frac{\sqrt{5}}{3}$.

Find the roots of the following quadratic equation by the factorisation method:
$3x^{2} + 5\sqrt{5}x - 10 = 0$

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Find the roots of the following quadratic equation by the factorisation method:$3x^{2} + 5\sqrt{5}x - 10 = 0$