Find the sum of the first $n$ terms and the sum of the first $5$ terms of the geometric series $1 + \frac{2}{3} + \frac{4}{9} + \dots$

  • A
    $S_n = 3[1 - (\frac{2}{3})^n], S_5 = \frac{211}{81}$
  • B
    $S_n = 3[1 - (\frac{2}{3})^n], S_5 = \frac{205}{81}$
  • C
    $S_n = 2[1 - (\frac{2}{3})^n], S_5 = \frac{211}{81}$
  • D
    $S_n = 3[1 - (\frac{3}{2})^n], S_5 = \frac{211}{81}$

Explore More

Similar Questions

If three successive terms of a $G.P.$ with common ratio $r$ $(r > 1)$ are the lengths of the sides of a triangle,and $[r]$ denotes the greatest integer less than or equal to $r$,then $3[r] + [-r]$ is equal to:

Consider the quadratic equation $(n^2 - 2n + 2)x^2 - 3x + (n^2 - 2n + 2) = 0, n \in R$. Let $\alpha$ be the minimum value of the product of its roots and $\beta$ be the maximum value of the sum of its roots. Then the sum of the first six terms of the $G$.$P$.,whose first term is $\alpha$ and the common ratio is $\frac{\alpha}{\beta}$, is:

If $n$ geometric means between $a$ and $b$ are $G_1, G_2, ..., G_n$ and a single geometric mean is $G$,then the true relation is

Difficult
View Solution

If $G$ is the geometric mean between $x$ and $y$,then the value of $\frac{1}{G^2 - x^2} + \frac{1}{G^2 - y^2}$ is:

Difficult
View Solution

$A$ geometric progression consists of positive terms. If each term is equal to the sum of the next two terms,what is the common ratio of the progression?

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo