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(A) The circuit consists of a diode connected in parallel with a resistor $R$. The total current $I$ is the sum of the current through the resistor $(

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(A) The circuit consists of a diode connected in parallel with a resistor $R$. The total current $I$ is the sum of the current through the resistor $(I_R)$ and the current through the diode $(I_D)$,i.e.,$I = I_R + I_D$.$1$. When the voltage $V$ is negative (reverse bias),the diode acts as an open circuit (assuming an ideal diode). Thus,the entire current flows through the resistor $R$. According to Ohm's law,$I = V / R$. This results in a straight-line graph passing through the origin with a slope of $1/R$ in the third quadrant.$2$. When the voltage $V$ is positive (forward bias),the diode starts conducting significantly after the knee voltage. The current through the diode is given by $I_D = I_s (e^{V / n V_T} - 1)$. The total current $I = V / R + I_s (e^{V / n V_T} - 1)$. This results in an exponential increase in current in the first quadrant.Combining these,the characteristic curve shows a linear relationship in the negative $V$ region and an exponential growth in the positive $V$ region,which matches the graph in option $(A)$.

For a diode connected in parallel with a resistor,which is the most likely current $I$-voltage $V$ characteristic?

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