For a given A.P.,a=1 and d=2. Then,S_{10} = d | vedclass

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(B) Given: First term $a = 1$,common difference $d = 2$,and number of terms $n = 10$.The formula for the sum of the first $n$ terms of an $A.P.$ is $S

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$100$

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(B) Given: First term $a = 1$,common difference $d = 2$,and number of terms $n = 10$.The formula for the sum of the first $n$ terms of an $A.P.$ is $S_n = \frac{n}{2} [2a + (n - 1)d]$.Substituting the values into the formula:$S_{10} = \frac{10}{2} [2(1) + (10 - 1)2]$$S_{10} = 5 [2 + (9 	imes 2)]$$S_{10} = 5 [2 + 18]$$S_{10} = 5 	imes 20 = 100$.Therefore,the sum of the first $10$ terms is $100$.

For a given $A.P.$,$a=1$ and $d=2$. Then,$S_{10} = \dots$

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