For a given frequency distribution,$A = 450, c = 100, \Sigma f_{i} u_{i} = -20$ and $\Sigma f_{i} = 20$. Then,the mean $\bar{x} = \ldots$
- A$275$
- B$350$
- C$450$
- D$430$
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Similar Questions
For a given frequency distribution,$n=100, A=20$ and $\bar{x}=20$. Then,$\Sigma f_{i} d_{i}=\ldots \ldots \ldots . .$
Medium
View SolutionFind the mean of the following frequency distribution:
Class
$21-25$
$26-30$
$31-35$
$36-40$
$41-45$
$46-50$
$51-55$
Frequency
$18$
$32$
$30$
$40$
$25$
$15$
$40$
(in $.675$)
| Class | $21-25$ | $26-30$ | $31-35$ | $36-40$ | $41-45$ | $46-50$ | $51-55$ |
| Frequency | $18$ | $32$ | $30$ | $40$ | $25$ | $15$ | $40$ |
Easy
View SolutionThe mean of the following frequency distribution is $18$. Find the missing frequency $f$.
Class $11-13$ $13-15$ $15-17$ $17-19$ $19-21$ $21-23$ $23-25$ Frequency $3$ $6$ $9$ $13$ $f$ $5$ $4$
| Class | $11-13$ | $13-15$ | $15-17$ | $17-19$ | $19-21$ | $21-23$ | $23-25$ |
| Frequency | $3$ | $6$ | $9$ | $13$ | $f$ | $5$ | $4$ |
Medium
View SolutionThe mean of the following frequency distribution is $52$. Find the missing frequency $f$.
Class $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ Frequency $5$ $3$ $4$ $f$ $2$ $6$ $13$
| Class | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ | $60-70$ | $70-80$ |
| Frequency | $5$ | $3$ | $4$ | $f$ | $2$ | $6$ | $13$ |
Medium
View SolutionThe mean of the following frequency distribution is $28.5$ and the total frequency is $60$. Find the missing frequencies $f_{1}$ and $f_{2}$.
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$ Frequency $6$ $f_1$ $20$ $15$ $f_2$ $4$
| Class | $0-10$ | $10-20$ | $20-30$ | $30-40$ | $40-50$ | $50-60$ |
| Frequency | $6$ | $f_1$ | $20$ | $15$ | $f_2$ | $4$ |
Medium
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