For an A.P.,T_{n} = ldots ldots ldots ldots ( | vedclass

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(B) The sum of the first $n$ terms of an $A.P.$ is denoted by $S_{n} = T_{1} + T_{2} + \ldots + T_{n-1} + T_{n}$.Similarly,the sum of the first $(n-1)

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$S_{n} - S_{n-1}$

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(B) The sum of the first $n$ terms of an $A.P.$ is denoted by $S_{n} = T_{1} + T_{2} + \ldots + T_{n-1} + T_{n}$.Similarly,the sum of the first $(n-1)$ terms is $S_{n-1} = T_{1} + T_{2} + \ldots + T_{n-1}$.By subtracting the two equations,we get:$S_{n} - S_{n-1} = (T_{1} + T_{2} + \ldots + T_{n-1} + T_{n}) - (T_{1} + T_{2} + \ldots + T_{n-1})$$S_{n} - S_{n-1} = T_{n}$.Thus,for $n > 1$,the $n^{th}$ term is given by $T_{n} = S_{n} - S_{n-1}$.

For an $A.P.$,$T_{n} = \ldots \ldots \ldots \ldots (n > 1)$

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