For the circuit shown in the figure,the curre | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) In an $AC$ circuit with an inductor and a capacitor connected in parallel,the current through the inductor $(I_L)$ lags the voltage by $90^{\circ}

Vedclass · Accepted Answer

$I = 0.5\,A$

Vedclass · Answer

(C) In an $AC$ circuit with an inductor and a capacitor connected in parallel,the current through the inductor $(I_L)$ lags the voltage by $90^{\circ}$,and the current through the capacitor $(I_C)$ leads the voltage by $90^{\circ}$.Thus,the currents $I_L$ and $I_C$ are in opposite phases,i.e.,they have a phase difference of $180^{\circ}$.The total current $I$ drawn from the generator is the vector sum of these currents:$I = |I_L - I_C|$Given $I_L = 0.9\,A$ and $I_C = 0.4\,A$.Therefore,$I = |0.9 - 0.4| = 0.5\,A$.

For the circuit shown in the figure,the current through the inductor is $0.9\,A$ while the current through the capacitor is $0.4\,A$. Then

Similar Questions

When a capacitor is connected in series with an $LR$ circuit, the alternating current flowing in the circuit:

What is the impedance of an $L-C-R$ series $AC$ circuit?

In the given circuit,the magnitudes of $V_{L}$ and $V_{C}$ are twice that of $V_{R}$. Given that $f=50\,Hz$ and $R=5\,\Omega$,the inductance of the coil is $\frac{1}{K\pi}\,mH$. The value of $K$ is:

In a series $LCR$ circuit,if the current leads the source voltage,then

In a series $LR$ circuit,$X_L = 3R$. Now,a capacitor with $X_C = R$ is added in series. What is the ratio of the new power factor to the old power factor?

Vedclass Test Series

Exam Paper Generator

Online Exam Module