(C) The given $A.P.$ is $85, 80, 75, \ldots, -30$.Here,the first term $a = 85$ and the common difference $d = 80 - 85 = -5$.The last term $l = -30$.To

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(C) The given $A.P.$ is $85, 80, 75, \ldots, -30$.Here,the first term $a = 85$ and the common difference $d = 80 - 85 = -5$.The last term $l = -30$.To find the $n^{th}$ term from the end of an $A.P.$,the formula is $l - (n - 1)d$.Here,we need the $5^{th}$ term from the end,so $n = 5$.$5^{th} \text{ term from the end} = l - (5 - 1)d$$= -30 - (4)(-5)$$= -30 + 20$$= -10$.

Class 10 Mathematics Arithmetic Progressions Mix Examples - Arithmetic Progressions

Medium

For the finite $A.P.$ $85, 80, 75, \ldots, -30,$ find the $5^{th}$ term from the end.

A
$96$
B
$-40$
C
$-10$
D
$-100$

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Arithmetic Progressions

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Mix Examples - Arithmetic Progressions

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For the finite $A.P.$ $85, 80, 75, \ldots, -30,$ find the $5^{th}$ term from the end.

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For an $A.P.$,the first term is $5$ and the common difference is $3$. Then,the $15^{th}$ term of the $A.P.$ is..........

Can any term of the $A.P.$ $242, 236, 230, \ldots$ be $0$? If yes,which term?

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Verify that each of the following is an $AP$,and then write its next three terms.
$a, 2a+1, 3a+2, 4a+3, \ldots$