For the gaseous reaction,$N_2O_5 \rightarrow 2NO_2 + \frac{1}{2}O_2$,the rate can be expressed as:
$-\frac{d[N_2O_5]}{dt} = K_1[N_2O_5]$
$+\frac{d[NO_2]}{dt} = K_2[N_2O_5]$
$+\frac{d[O_2]}{dt} = K_3[N_2O_5]$
The correct relation between $K_1, K_2$ and $K_3$ is:

  • A
    $K_1 = 2K_2 = 4K_3$
  • B
    $2K_1 = K_2 = 4K_3$
  • C
    $2K_1 = 3K_2 = 4K_3$
  • D
    $4K_1 = 2K_2 = K_3$

Explore More

Similar Questions

If the concentration of a first-order reaction is increased by $x$ times,then the rate constant $(k)$ becomes

Half-life of a reaction is found to be inversely proportional to the fifth power of its initial concentration,the order of reaction is

If $a$ is the initial concentration and $n$ is the order of the reaction and the half-life period is $T$,then:

For a particular reaction,the variation of the rate constant with temperature is given by $\ln k_t = \ln k_0 + \left( \frac{\ln (2.5)}{10} \right) \times t$ $(t \geqslant 0 \, ^{\circ}C)$. Here,$k_0$ is the rate constant at $0 \, ^{\circ}C$ and $k_t$ is the rate constant at $t \, ^{\circ}C$. The temperature coefficient of the reaction,assuming that the rate constant increases by the same factor for every $10 \, ^{\circ}C$ rise in temperature,is:

Difficult
View Solution

Which one of the following statements regarding the order of a reaction is not correct?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo