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(C) The reaction of an alkyl-substituted benzene with $Br_2$ in the presence of $UV$ light (or heat) proceeds via a free radical mechanism.This reacti

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$3-$($1$-bromoethyl)benzonitrile

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(C) The reaction of an alkyl-substituted benzene with $Br_2$ in the presence of $UV$ light (or heat) proceeds via a free radical mechanism.This reaction is a free radical substitution that occurs at the benzylic position.The benzylic hydrogen is abstracted to form a stable benzylic radical,which then reacts with $Br_2$ to form the monobrominated product.In the given molecule,$3-	ext{ethylbenzonitrile}$,the benzylic carbon is the $CH_2$ group attached to the benzene ring.Therefore,the bromine atom will substitute one of the hydrogen atoms on this benzylic carbon,resulting in $3-(1-	ext{bromoethyl})benzonitrile$ as the major product.

For the given reaction,what is the major product '$A$'?
$3-\text{ethylbenzonitrile} + Br_2 \xrightarrow{UV \text{ light}} A$

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For the given reaction,what is the major product '$A$'?$3-\text{ethylbenzonitrile} + Br_2 \xrightarrow{UV \text{ light}} A$