Give the value of acceleration due to gravity at height $12\, km$ from the surface of earth. (in $, m/s^2$)

If the value of $g$ (acceleration due to gravity) at the Earth's surface is $10 \ m/s^2$,what is its value in $m/s^2$ at the center of the Earth,assuming the Earth is a sphere of radius $R$ meters with uniform mass density?

If the earth stops rotating on its own axis,there will be no variation in the weight of our bodies at:

The time period of a simple pendulum is $T_1$ when on the Earth's surface and $T_2$ when taken to a height $h = 2R$ above the Earth's surface, where $R$ is the radius of the Earth. The ratio $T_1 : T_2$ is:

If the earth stops rotating,the value of $g$ at the equator will

Suppose that the force of earth's gravity suddenly disappears,choose the correct answer out of the following statements.