Given that v is speed,r is the radius,and g i | vedclass

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(A) The dimensions of the given physical quantities are:$v = [LT^{-1}]$$r = [L]$$g = [LT^{-2}]$Now,check the dimensions of the expression $\frac{v^2}{

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$v^2 / rg$

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(A) The dimensions of the given physical quantities are:$v = [LT^{-1}]$$r = [L]$$g = [LT^{-2}]$Now,check the dimensions of the expression $\frac{v^2}{rg}$:Dimension of $v^2 = [LT^{-1}]^2 = [L^2 T^{-2}]$Dimension of $rg = [L] \cdot [LT^{-2}] = [L^2 T^{-2}]$Therefore,the dimension of $\frac{v^2}{rg} = \frac{[L^2 T^{-2}]}{[L^2 T^{-2}]} = [M^0 L^0 T^0]$.This expression is dimensionless. This quantity represents $	an 	heta$ in the context of the angle of banking for a vehicle on a curved road.

Given that $v$ is speed,$r$ is the radius,and $g$ is the acceleration due to gravity. Which of the following is dimensionless?

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