Half the perimeter of a rectangular garden,whose length is $4\, m$ more than its width,is $36\, m$. Find the dimensions of the garden.

(N/A) Let the width of the garden be $x$ and the length be $y$.
According to the question:
$y - x = 4$ $...(1)$
$y + x = 36$ $...(2)$
From equation $(1)$,$y = x + 4$. The table of values is:

$x$	$0$	$8$	$12$
$y$	$4$	$12$	$16$

From equation $(2)$,$y = 36 - x$. The table of values is:

$x$	$0$	$36$	$16$
$y$	$36$	$0$	$20$

By plotting these lines on a graph,we observe that they intersect at the point $(16, 20)$.
Therefore,the width of the garden is $16\, m$ and the length is $20\, m$.