Identify the compound which has the maximum n | vedclass

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(D) Key Idea: The number of no-bond resonance (hyperconjugation) structures is equal to the number of $\alpha$-hydrogen atoms present on the carbon at

Vedclass · Accepted Answer

Toluene $(C_6H_5-CH_3)$

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(D) Key Idea: The number of no-bond resonance (hyperconjugation) structures is equal to the number of $\alpha$-hydrogen atoms present on the carbon atom directly attached to the benzene ring.$(a)$ tert-Butylbenzene: The $\alpha$-carbon has $0$ $H$-atoms. Number of hyperconjugation structures = $0$.$(b)$ Ethylbenzene: The $\alpha$-carbon $(CH_2)$ has $2$ $H$-atoms. Number of hyperconjugation structures = $2$.$(c)$ Isopropylbenzene: The $\alpha$-carbon $(CH)$ has $1$ $H$-atom. Number of hyperconjugation structures = $1$.$(d)$ Toluene: The $\alpha$-carbon $(CH_3)$ has $3$ $H$-atoms. Number of hyperconjugation structures = $3$.Since toluene has the maximum number of $\alpha$-hydrogen atoms $(3)$,it has the maximum number of no-bond resonance structures. Hence,option $(d)$ is the correct answer.

$(A)$. Inductive effect	$(I)$. Delocalization of $\pi$ electrons
$(B)$. Hyper-conjugation	$(II)$. Displacement of $\pi$ electrons
$(C)$. Resonance effect	$(III)$. Delocalization of $\sigma$ electrons
	$(IV)$. Displacement of $\sigma$ electrons

Identify the compound which has the maximum number of no-bond resonance (hyperconjugation) structures.

Similar Questions

The following effect is known as . . . . . .

In $CH_3(3) - CH_2(2) - CH_2(1) - Cl$,give the increasing order of the inductive effect for carbon atoms $1, 2,$ and $3$.

Which pair of groups exhibits the $(-I)$ effect?

Which of the following statements are $TRUE$?
$(I)$ Inductive effect operates through the $\sigma$ bond
$(II)$ Resonance effect operates through the $\pi$ bond
$(III)$ Inductive effects operate through the $\pi$ bond
$(IV)$ Resonance effect operates through the $\sigma$ bond

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