Identify the substance oxidised,reduced,oxidising agent,and reducing agent for each of the following reactions:
$(a)$ $2AgBr_{(s)} + C_6H_6O_{2(aq)} \to 2Ag_{(s)} + 2HBr_{(aq)} + C_6H_4O_{2(aq)}$
$(b)$ $HCHO_{(l)} + 2[Ag(NH_3)_2]^+_{(aq)} + 3OH^-_{(aq)} \to 2Ag_{(s)} + HCOO^-_{(aq)} + 2NH_{3(aq)} + 2H_2O_{(l)}$
$(c)$ $HCHO_{(l)} + 2Cu^{2+}_{(aq)} + 5OH^-_{(aq)} \to Cu_2O_{(s)} + HCOO^-_{(aq)} + 3H_2O_{(l)}$
$(d)$ $N_2H_{4(l)} + 2H_2O_{2(l)} \to N_{2(g)} + 4H_2O_{(l)}$
$(e)$ $Pb_{(s)} + PbO_{2(s)} + 2H_2SO_{4(aq)} \to 2PbSO_{4(s)} + 2H_2O_{(l)}$
$(a)$ $2AgBr_{(s)} + C_6H_6O_{2(aq)} \to 2Ag_{(s)} + 2HBr_{(aq)} + C_6H_4O_{2(aq)}$
$(b)$ $HCHO_{(l)} + 2[Ag(NH_3)_2]^+_{(aq)} + 3OH^-_{(aq)} \to 2Ag_{(s)} + HCOO^-_{(aq)} + 2NH_{3(aq)} + 2H_2O_{(l)}$
$(c)$ $HCHO_{(l)} + 2Cu^{2+}_{(aq)} + 5OH^-_{(aq)} \to Cu_2O_{(s)} + HCOO^-_{(aq)} + 3H_2O_{(l)}$
$(d)$ $N_2H_{4(l)} + 2H_2O_{2(l)} \to N_{2(g)} + 4H_2O_{(l)}$
$(e)$ $Pb_{(s)} + PbO_{2(s)} + 2H_2SO_{4(aq)} \to 2PbSO_{4(s)} + 2H_2O_{(l)}$
(N/A)
| Reaction | Oxidised Species | Reduced Species | Oxidising Agent | Reducing Agent |
|---|---|---|---|---|
| $(a)$ | $C_6H_6O_{2(aq)}$ | $AgBr_{(s)}$ | $AgBr_{(s)}$ | $C_6H_6O_{2(aq)}$ |
| $(b)$ | $HCHO_{(l)}$ | $[Ag(NH_3)_2]^+_{(aq)}$ | $[Ag(NH_3)_2]^+_{(aq)}$ | $HCHO_{(l)}$ |
| $(c)$ | $HCHO_{(l)}$ | $Cu^{2+}_{(aq)}$ | $Cu^{2+}_{(aq)}$ | $HCHO_{(l)}$ |
| $(d)$ | $N_2H_{4(l)}$ | $H_2O_{2(l)}$ | $H_2O_{2(l)}$ | $N_2H_{4(l)}$ |
| $(e)$ | $Pb_{(s)}$ | $PbO_{2(s)}$ | $PbO_{2(s)}$ | $Pb_{(s)}$ |
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Which of the following reactions are correct? (Ignore balancing of the reactions)
$(I)$ $Al + NaOH \xrightarrow{\Delta} NaAlO_2 + H_2$
$(II)$ $P_4 + NaOH + H_2O \to NaH_2PO_2 + PH_3$
$(III)$ $S + NaOH \to Na_2S_2O_3 + Na_2S + H_2O$
$(I)$ $Al + NaOH \xrightarrow{\Delta} NaAlO_2 + H_2$
$(II)$ $P_4 + NaOH + H_2O \to NaH_2PO_2 + PH_3$
$(III)$ $S + NaOH \to Na_2S_2O_3 + Na_2S + H_2O$
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View Solution$KMnO_4$ reacts with oxalic acid according to the equation:
$2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \to 2Mn^{2+} + 10CO_2 + 8H_2O$
Here $20 \ mL$ of $0.1 \ M \ KMnO_4$ is equivalent to:
$2MnO_4^- + 5C_2O_4^{2-} + 16H^+ \to 2Mn^{2+} + 10CO_2 + 8H_2O$
Here $20 \ mL$ of $0.1 \ M \ KMnO_4$ is equivalent to:
DifficultAIIMS 2013
View SolutionWhich of the following is oxidised by $SO_2$?
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View Solution$H_2S$ acts only as a reducing agent while $SO_2$ can act both as a reducing and oxidizing agent because
Medium
View SolutionConsider the reactions:
$(a)$ $6 CO_{2(g)} + 6 H_{2}O_{(l)} \rightarrow C_{6}H_{12}O_{6(aq)} + 6 O_{2(g)}$
$(b)$ $O_{3(g)} + H_{2}O_{2(l)} \rightarrow H_{2}O_{(l)} + 2 O_{2(g)}$
Why is it more appropriate to write these reactions as:
$(a)$ $6 CO_{2(g)} + 12 H_{2}O_{(l)} \rightarrow C_{6}H_{12}O_{6(aq)} + 6 H_{2}O_{(l)} + 6 O_{2(g)}$
$(b)$ $O_{3(g)} + H_{2}O_{2(l)} \rightarrow H_{2}O_{(l)} + O_{2(g)} + O_{2(g)}$
Also,suggest a technique to investigate the path of the above $(a)$ and $(b)$ redox reactions.
$(a)$ $6 CO_{2(g)} + 6 H_{2}O_{(l)} \rightarrow C_{6}H_{12}O_{6(aq)} + 6 O_{2(g)}$
$(b)$ $O_{3(g)} + H_{2}O_{2(l)} \rightarrow H_{2}O_{(l)} + 2 O_{2(g)}$
Why is it more appropriate to write these reactions as:
$(a)$ $6 CO_{2(g)} + 12 H_{2}O_{(l)} \rightarrow C_{6}H_{12}O_{6(aq)} + 6 H_{2}O_{(l)} + 6 O_{2(g)}$
$(b)$ $O_{3(g)} + H_{2}O_{2(l)} \rightarrow H_{2}O_{(l)} + O_{2(g)} + O_{2(g)}$
Also,suggest a technique to investigate the path of the above $(a)$ and $(b)$ redox reactions.
Medium
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