If xy = c^2 where c is a constant,then frac{d | vedclass

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(D) Given the equation $xy = c^2$,where $c$ is a constant.We can express $y$ in terms of $x$ as $y = c^2 x^{-1}$.Now,differentiate both sides with res

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$\frac{-y}{x}$

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(D) Given the equation $xy = c^2$,where $c$ is a constant.We can express $y$ in terms of $x$ as $y = c^2 x^{-1}$.Now,differentiate both sides with respect to $x$ using the power rule:$\frac{dy}{dx} = c^2 \cdot (-1) \cdot x^{-2} = -\frac{c^2}{x^2}$.Since $c^2 = xy$,substitute this back into the expression:$\frac{dy}{dx} = -\frac{xy}{x^2} = -\frac{y}{x}$.

If $xy = c^2$ where $c$ is a constant,then $\frac{dy}{dx}$ is equal to

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