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(D) For isotonic solutions,the osmotic pressure $\pi$ is the same: $\pi_A = \pi_B$.The formula for osmotic pressure is $\pi = CRT = \frac{n}{V} RT$,wh

Vedclass · Accepted Answer

$177$

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(D) For isotonic solutions,the osmotic pressure $\pi$ is the same: $\pi_A = \pi_B$.The formula for osmotic pressure is $\pi = CRT = \frac{n}{V} RT$,where $n$ is the number of moles and $V$ is the volume in litres.Let $M_A$ and $M_B$ be the molar masses of protein $A$ and $B$ respectively.For protein $A$: $n_A = \frac{0.73}{M_A}$,$V_A = 0.25 \ L$.For protein $B$: $n_B = \frac{1.65}{M_B}$,$V_B = 1 \ L$.Equating the osmotic pressures: $\frac{0.73}{M_A 	imes 0.25} RT = \frac{1.65}{M_B 	imes 1} RT$.$\frac{M_A}{M_B} = \frac{0.73}{0.25 	imes 1.65} = \frac{0.73}{0.4125} \approx 1.7696$.Rounding to the nearest integer for the value $	imes 10^{-2}$,we get $177$.

If $250 \ cm^3$ of an aqueous solution containing $0.73 \ g$ of a protein $A$ is isotonic with one litre of another aqueous solution containing $1.65 \ g$ of a protein $B,$ at $298 \ K,$ the ratio of the molecular masses of $A$ and $B$ is..........$\times 10^{-2}$ (to the nearest integer).

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