If sqrt{x} - sqrt{y} = 1 and sqrt{x} + sqrt{y | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Given equations are:$(1)$ $\sqrt{x} - \sqrt{y} = 1$$(2)$ $\sqrt{x} + \sqrt{y} = 17$Adding equations $(1)$ and $(2)$:$(\sqrt{x} - \sqrt{y}) + (\sqr

Vedclass · Accepted Answer

$72$

Vedclass · Answer

(A) Given equations are:$(1)$ $\sqrt{x} - \sqrt{y} = 1$$(2)$ $\sqrt{x} + \sqrt{y} = 17$Adding equations $(1)$ and $(2)$:$(\sqrt{x} - \sqrt{y}) + (\sqrt{x} + \sqrt{y}) = 1 + 17$$2\sqrt{x} = 18$$\sqrt{x} = 9$Substituting $\sqrt{x} = 9$ into equation $(2)$:$9 + \sqrt{y} = 17$$\sqrt{y} = 17 - 9 = 8$Now,we need to find $\sqrt{xy}$:$\sqrt{xy} = \sqrt{x} \cdot \sqrt{y}$$\sqrt{xy} = 9 \cdot 8 = 72$Therefore,the value is $72$.

If $\sqrt{x} - \sqrt{y} = 1$ and $\sqrt{x} + \sqrt{y} = 17$,then $\sqrt{xy} = ?$

Similar Questions

$40.83 \times 1.02 \times 1.2 = ?$

What mathematical operation should come at the place of $?$ in the equation $2 ? 6 - 12 \div 4 + 2 = 11$?

$8.88 \times 88.8 \times 88 = ?$

If $x+\frac{2}{3+\frac{4}{5+\frac{7}{6}}}=10$,then the value of $x$ is

If the difference between $\frac{4}{5}$ part and $\frac{3}{4}$ part of a number is $4,$ what is the number?

Vedclass Test Series

Exam Paper Generator

Online Exam Module