If A = { 2, 4, 5 } and B = { 7, 8, 9 },then n | vedclass

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(B) The Cartesian product $A 	imes B$ is the set of all ordered pairs $(a, b)$ such that $a \in A$ and $b \in B$.Given $A = \{ 2, 4, 5 \}$,the number

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$9$

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(B) The Cartesian product $A 	imes B$ is the set of all ordered pairs $(a, b)$ such that $a \in A$ and $b \in B$.Given $A = \{ 2, 4, 5 \}$,the number of elements in $A$ is $n(A) = 3$.Given $B = \{ 7, 8, 9 \}$,the number of elements in $B$ is $n(B) = 3$.The number of elements in the Cartesian product is given by the formula $n(A 	imes B) = n(A) 	imes n(B)$.Therefore,$n(A 	imes B) = 3 	imes 3 = 9$.

If $A = \{ 2, 4, 5 \}$ and $B = \{ 7, 8, 9 \}$,then $n(A \times B)$ is equal to

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