If A = { x : x^2 - 5x + 6 = 0 }, B = { 2, 4 } | vedclass

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(A) First,we solve the quadratic equation for set $A$: $x^2 - 5x + 6 = 0$.Factoring the quadratic,we get $(x - 2)(x - 3) = 0$,so $x = 2$ or $x = 3$. T

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$\{(2, 4), (3, 4)\}$

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(A) First,we solve the quadratic equation for set $A$: $x^2 - 5x + 6 = 0$.Factoring the quadratic,we get $(x - 2)(x - 3) = 0$,so $x = 2$ or $x = 3$. Thus,$A = \{2, 3\}$.Next,we find the intersection of sets $B$ and $C$: $B \cap C = \{2, 4\} \cap \{4, 5\} = \{4\}$.Finally,we calculate the Cartesian product $A 	imes (B \cap C) = \{2, 3\} 	imes \{4\}$.This results in the set of ordered pairs $\{(2, 4), (3, 4)\}$.

If $A = \{ x : x^2 - 5x + 6 = 0 \}, B = \{ 2, 4 \}, C = \{ 4, 5 \}$,then $A \times (B \cap C)$ is

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