If tan A = frac{1}{2} and tan B = frac{1}{3}, | vedclass

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(B) We use the formula for the tangent of a sum of two angles: $	an(A + B) = \frac{	an A + 	an B}{1 - 	an A 	an B}$.Substituting the given values

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$\frac{\pi}{4}$

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(B) We use the formula for the tangent of a sum of two angles: $	an(A + B) = \frac{	an A + 	an B}{1 - 	an A 	an B}$.Substituting the given values $	an A = \frac{1}{2}$ and $	an B = \frac{1}{3}$:$	an(A + B) = \frac{\frac{1}{2} + \frac{1}{3}}{1 - (\frac{1}{2})(\frac{1}{3})}$$= \frac{\frac{3+2}{6}}{1 - \frac{1}{6}}$$= \frac{\frac{5}{6}}{\frac{5}{6}} = 1$.Since $	an(A + B) = 1$,we have $A + B = 	an^{-1}(1)$.Therefore,$A + B = \frac{\pi}{4}$.

If $\tan A = \frac{1}{2}$ and $\tan B = \frac{1}{3},$ the value of $A + B$ is

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