If frac{log x}{2} = frac{log y}{3} = frac{log | vedclass

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(D) Let $\frac{\log x}{2} = \frac{\log y}{3} = \frac{\log z}{5} = k$.Then,$\log x = 2k$,$\log y = 3k$,and $\log z = 5k$.We need to find $yz$ in terms

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$x^4$

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(D) Let $\frac{\log x}{2} = \frac{\log y}{3} = \frac{\log z}{5} = k$.Then,$\log x = 2k$,$\log y = 3k$,and $\log z = 5k$.We need to find $yz$ in terms of $x$. Consider $\log(yz) = \log y + \log z$.Substituting the values,$\log(yz) = 3k + 5k = 8k$.Since $\log x = 2k$,we can write $8k = 4(2k) = 4 \log x = \log(x^4)$.Therefore,$\log(yz) = \log(x^4)$,which implies $yz = x^4$.

If $\frac{\log x}{2} = \frac{\log y}{3} = \frac{\log z}{5}$,then $yz$ in terms of $x$ is

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