If sqrt{3} tan theta = 1,then find the value | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Given that,$\sqrt{3} 	an 	heta = 1$.$	an 	heta = \frac{1}{\sqrt{3}}$.Since $	an 30^{\circ} = \frac{1}{\sqrt{3}}$,we have $	heta = 30^{\circ}

Vedclass · Accepted Answer

$-\frac{1}{2}$

Vedclass · Answer

(C) Given that,$\sqrt{3} 	an 	heta = 1$.$	an 	heta = \frac{1}{\sqrt{3}}$.Since $	an 30^{\circ} = \frac{1}{\sqrt{3}}$,we have $	heta = 30^{\circ}$.Now,substitute $	heta = 30^{\circ}$ into the expression $\sin^{2} 	heta - \cos^{2} 	heta$:$\sin^{2} 30^{\circ} - \cos^{2} 30^{\circ} = \left(\frac{1}{2}ight)^{2} - \left(\frac{\sqrt{3}}{2}ight)^{2}$.$= \frac{1}{4} - \frac{3}{4}$.$= \frac{1 - 3}{4} = -\frac{2}{4} = -\frac{1}{2}$.

If $\sqrt{3} \tan \theta = 1$,then find the value of $\sin^{2} \theta - \cos^{2} \theta$.

Similar Questions

In $\Delta ABC$,$m \angle C = 90^{\circ}$ and $\cos B = \frac{1}{2}$,then $\operatorname{cosec} A = \ldots$

If $\cot \theta = \frac{a}{b}$,then $\frac{\cos \theta - \sin \theta}{\cos \theta + \sin \theta} = \ldots$

If $\sin \theta = \frac{1}{2}$,then $\theta = \ldots \ldots \ldots \ldots$ (in $^\circ$)

If $\sin ^{2}(3 x+30^{\circ})+\cos ^{2}(2 x+45^{\circ})=1$,then $x = \dots$ (in $^{\circ}$)

If $\tan ^{2} \theta = \sin ^{2} \theta + \cos ^{2} \theta$,then $\theta = \ldots$ (in $^{\circ}$)

Vedclass Test Series

Exam Paper Generator

Online Exam Module