If x^{2}+6x+10 is divided by x+2,then the rem | vedclass

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(B) To find the remainder when a polynomial $p(x) = x^{2} + 6x + 10$ is divided by $x + 2$,we use the Remainder Theorem.According to the Remainder The

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$2$

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(B) To find the remainder when a polynomial $p(x) = x^{2} + 6x + 10$ is divided by $x + 2$,we use the Remainder Theorem.According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,the divisor is $x + 2$,which can be written as $x - (-2)$.Therefore,$a = -2$.Now,we calculate $p(-2)$:$p(-2) = (-2)^{2} + 6(-2) + 10$$p(-2) = 4 - 12 + 10$$p(-2) = 14 - 12$$p(-2) = 2$Thus,the remainder is $2$.

If $x^{2}+6x+10$ is divided by $x+2$,then the remainder is..........

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