If $p, q$ and $r$ are three propositions,then which of the following combination of truth values of $p, q$ and $r$ makes the logical expression $\{(p \vee q) \wedge ((\sim p) \vee r)\} \rightarrow ((\sim q) \vee r)$ false?

  • A
    $p = T, q = F, r = T$
  • B
    $p = T, q = T, r = F$
  • C
    $p = F, q = T, r = F$
  • D
    $p = T, q = F, r = F$

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